Question

Two vertices of a rectangle are( 6, -1)(6,9) and remaining two vertices are on Y-axis, then find the area of rectangle​

Answer 1

Answer:

Area of the rectangle is 60 unit².

Step-by-step explanation:

Given:

Vertices of the rectangle are ( 6 , -1 ) and ( 6 , 9 )

Remaining to vertices of the rectangle are on y-axis.

To find: Are of the cube.

From the given information,

Other two vertices should be ( 0 , -1 ) and ( 0 , 9 )

Graph is attached.

Length of the rectangle, AB = $\sqrt{(6-0)^2+(9-9)^2}=\sqrt{6^2}=6\:units$

Breadth of the rectangle, CB = $\sqrt{(6-6)^2+(9-(-1))^2}=\sqrt{10^2}=10\:units$

So, Area of the Rectangle = length × breadth = 6 × 10 = 60 unit²

Therefore, Area of the rectangle is 60 unit².

Answer 2

Answer:

the answer to the above question is 60sq cm

Step-by-step explanation:

the vertices have many options but keep in mind the shape of the figure

alright

have a good time