Question

Two vertices of a triangle are (0, 2) and (4, 3). If its orthocenter is at the origin, then its third vertex lies in which quadrant?
(A) third (B) second
(C) first (D) fourth

Answer 1

mBD×mAD=−1

⇒(3−2/4−0)×(b−0a−0)=−1

⇒b+4a=0mAB×mCF=−1

⇒((b−2)a−0)×(34)=−1

⇒3b−6=−4a

⇒4a+3b=6a=−34,

b=3

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