Two vertices of a triangle are (3,-5( and (-7,4) .If its centroid is (2,-1) ,find the third vertex
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13
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A( 3,-5) B( -7,4)
G = (2,-1)
( 2,-1) = X1+X2+x3/3 + y1+y2+y3 /3
(2,-1) = 3 + (-7) + x/3 , -5+4 +y /3
(2,-1)= 3-7+x/3,-1+y/3
(2,-1)= -4+x/3,-1+y/3
now equating x and y coordinates
we get, 2= -4 + x/3
6 = -4 + x
x = 10
-1 = -1+y/3
-3 = -1+y
-2 = y
the third vertex is (10,-2)
Answered by
4
Answer:
(10,-2) is the required answer
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