Question

two vertices of an isosceles triangle are 2,8 and 10,2.find the third vertex if the length of the equal sides is 10 units. please give me its appropriate solution, ❤️​

Answer 1

Answer:

Step-by-step explanation:

let the third vertex is A(x,y)

and the given vertex are of base of isosceles Triangle B(2,8) and C(10,2)

As we know that two sides of isosceles Triangle are equal

Thus we calculate AB and AC by distance formula

AB=AC

put this value in

by this way we can solve the value of y by solving Quadratic equation.

thus value of x