Question

Two vertices of triangle are A(2,3)&B(1,-3)&its centroid is (3,0) then the co -ordinate is

Answer 1

the coordinates are 6,0

Answer 2

$\huge\bold {ANSWER}$

The centriod of a triangle is the point of intersection of its median and divides each median in the ratio 2:1.

Let the coordinates of point A be$(x_1,y_1)$

And the coordinates of point B be $(x_2,y_2)$

And of C be $(x_3,y_3)[tex] and the centriod be P with its coordinates be (x, y) For [tex]x_3$

So, by to find coordinates of third vertices

x=$\frac{x1 +x2 +x_3}{3}$

3=$\frac{2 + 1 +x_3}{3}$

On cross multiplication,

$9=3+ x_3$

$9-3=x_3$

$6= x_3$

For$y_3,$

y=$\frac{y1 +y2 +y3}{3}$

0=$\frac{3 + (-3)+x3}{3}$

On cross multiplication,

$0=3-3+ y_3$

$0=y_3$

So, the coordinates of third vertices is (6,0).