Math, asked by tomarpratibha1p73r1g, 1 year ago

Two vessel a and b contain milk and water in ratio 8:5 and5:2 respectively. The ratio in which these two mixture be mixed to get a new mixture containing 69-3/11 milk is

Answers

Answered by Anonymous
6
HEY DEAR ... ✌

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Let cost of 1 liter milk be Rs. 1.
Milk in 1 liter mix. in A = 8/13 liter, C.P. of 1 liter mix. in A = Rs. 8/13.
Milk in 1 liter mix. in B = 5/7 liter, C.P. of 1 liter mix. in B = Rs. 5/7.
Milk in 1 liter of final mix. = (900/13 x 1/100 x 1) = 9/13 liter.
Mean price = Rs.9/13.
By the rule of alligation, we have:
C.P. of 1 liter mixture in AC.P. of 1 liter mixture in B .

so Required ratio = 2/91 : 1/13 = 2 : 7

HOPE , IT HELPS ... ✌
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