Two vessels A and B are filled with same gas where volume, temperature and pressure in vessel A is twice
the volume, temperature and pressure in vessel B. calculate the ratio of number molecule of gas in vessel A
to that in vessel B.
Answers
Answered by
9
PV=nRT
∴n
B
=
RT
PV
and n
A
=
R×2T
2P×2V
or n
A
=
RT
2PV
∴
n
B
n
A
=
1
2
.
Answered by
5
Answer:
Let us consider that there are 100 g of each Hydrogen and Helium in two separate containers. Then the no.of moles of Hydrogen and Helium in each vessel would be,
No.of moles of H2= Wt./ Mol.Wt.=100/2 =50 No.of moles of He=Wt/Mol.Wt=100/4=25.
The Press of the gas in vessels of equal volume will be proportional to the no.of moles of the gas.
The Pressure of Hydrogen gas with 50 moles is 2 atm, then the Pressure of Helium gas with 25 moles will be = 2 x 25/50= 1 atm.
So the Pressure of Helium gas will be 1 atm.
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