Two water tap a and b can fill a tank in 12 hours . tap a takes 10 hour less than the time taken by tap b to fill tank separately . find time taken by tap b to fill the tank
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arfa34:
what's the answer
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let the time taken by tap a be x and tap b ne y
12x+12y=1
x=y-10
12(y-10)=y-10
12y-120=y-10
12y-120+10=y
12y-y=120-10
11y=110
y=10
therefore time taken by tap b to fill the tank is 10 hours
12x+12y=1
x=y-10
12(y-10)=y-10
12y-120=y-10
12y-120+10=y
12y-y=120-10
11y=110
y=10
therefore time taken by tap b to fill the tank is 10 hours
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