Two water taps together can fill a tank in 6 hour and 40 minutes. Find the time each will take to fill the tank if one of the two pipes can fill it in 3 hours less than the other.
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Answer:
Step-by-step explanation:
let the first pipe fills the tank in x hrs
1/x+1/x-3=3/20
(2x-3)/(x^2-3x)=3/20
40x-60=3x^2-9x
3x^2-49x+60=0
3x^2-45x-4x+60=0
3x(x-15)-4(x-15)=0
x=15,x=4/3
pipe 1=15 pipe2=12
pipe1==4/3,pipe2=5/3
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