Question

Two weather balloons A and B were released into the atmosphere. At midday the altitude of A was 10000m, the altitude of B was 12000m and the angle of elevation of B from A was 13degrees. Calculate the distance to the nearest 100m, of B from A.

Answer 1

Given, Distance between twvo

buildings A and B =100 m

Height of the building A(AE) = zm

Height of the building B(BD) = (z +

y) m

i)In AEAB, ZEAB ==90

tan50° = AE

1.192= T0

r= 1.192 x 100

r 119.2 m -

ii) In AECD, ZECD = 90°

tan20 CE

0.3639 =cd/ce

0.3639 = 100

0.3639 x 100 =y

y 0.3639 x 100

y = 36.39 m --

(2)

' Height of the building B

= BC + CD

= x+y

= 119.2 m +36.39 m

= 155.59 m

Therefore.,

.'. Height of the building B

155.59 m

Answer 2

Answer:

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Your answer on the upper attachment ☝️

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