Two weather balloons A and B were released into the atmosphere. At midday the altitude of A was 10000m, the altitude of B was 12000m and the angle of elevation of B from A was 13degrees. Calculate the distance to the nearest 100m, of B from A.
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Given, Distance between twvo
buildings A and B =100 m
Height of the building A(AE) = zm
Height of the building B(BD) = (z +
y) m
i)In AEAB, ZEAB ==90
tan50° = AE
1.192= T0
r= 1.192 x 100
r 119.2 m -
ii) In AECD, ZECD = 90°
tan20 CE
0.3639 =cd/ce
0.3639 = 100
0.3639 x 100 =y
y 0.3639 x 100
y = 36.39 m --
(2)
' Height of the building B
= BC + CD
= x+y
= 119.2 m +36.39 m
= 155.59 m
Therefore.,
.'. Height of the building B
155.59 m
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