Question

Two weights A and B of 5kg and 10kg respectively are sliding down the inclined plane. What is the acceleration with which the weights will slide down?​

Answer 1

Answer:

0.50g

Explanation:

force acting down the incline = mg sin 30 = mg/2

thus acceleration of the block down the incline mg/2/m = g/2

therefore both the blocks move down with acceleration = g/2 = 0.50g

Answer 2

$\huge\bigstar\boxed{\red{\sf solution:-}}\bigstar$

mass of block a = 5kg

mass of block b = 10kg

$\huge\boxed{\pink{\sf to\: find:-}}$

acceleration of both the blocks relative to ground.

we know that the vector component along the incline can be given as:

$\boxed{\red{\tt mgsin(A) }}$

where, A is the given angle of inclination (30° in this case).

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the forces which will cause acceleration are:

• normal reaction between plane

• gravitational force

using Newton's second law of motion,

$\boxed{\blue{\tt force=mass×acc }}$

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using this expression for blocks a

•mgsin30° = (5) × a

•10×1/2 = a

• acc = 5m/s²

using this expression for block b

• 10×gsin30° = 10(a)

• 10×1/2 = a

• a = 5m/s²

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thus, block a and b will be moving together since acceleration of block a is greater than acceleration of block b

together acceleration:

•15×gsin30° = 15×a

• a = 5m/s²

Thus, both the blocks together will move at the acceleration of 5 m/s²

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