two wires a and b both with equal resistance are made of same material. if radius of wire b is doubled than that of a determine the ratio of their length
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Let radius of a and b be x and 2x respectively.
Given,
There densities are same as there material are same.
Resistance of a = Resistance of b = R(say)
Now,
R = ρ 1/A₁
Or A₁ = ρ/R
Or x² = ρ/R
Or x = √(ρ/R)
Also,
R = ρ 1/A₂
Or A₂ = ρ/R
Or 4x² = ρ/R
Or x² = ρ/4R
Or x = √(ρ/4R)
Now,
Ratio of lengths = √(ρ/R) / √(ρ/4R)
= √(ρ/R) / 1/2 √(ρ/R)
= 2
Thus ratio is 2:1
Given,
There densities are same as there material are same.
Resistance of a = Resistance of b = R(say)
Now,
R = ρ 1/A₁
Or A₁ = ρ/R
Or x² = ρ/R
Or x = √(ρ/R)
Also,
R = ρ 1/A₂
Or A₂ = ρ/R
Or 4x² = ρ/R
Or x² = ρ/4R
Or x = √(ρ/4R)
Now,
Ratio of lengths = √(ρ/R) / √(ρ/4R)
= √(ρ/R) / 1/2 √(ρ/R)
= 2
Thus ratio is 2:1
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