Question

Two wires of diameter 0.25 cm, one made of steel and the other m
loaded as shown in Fig. 9.13. The unloaded length of steel wire is 1
brass wire is 1.0 m. Compute the elongations of the steel and the bra
LLLLLLL
1.5 m
Steel
4.0 kg
1.0 m
Brass
6.0 kg​

Answer 1

Answer:

Given,

diametre of wires = 0.25 cm

so, radius of wires ( r) = 1.25 × 10^-3 m

For steel wire

__________________

Tension in Steel wire ( F1) = 6g + 4g

= (10)g = 98 N

Length of steel wire (L1) = 1.5 m

Young's modulus (Y1) = 2.× 10¹¹ Pa

we know,

change in length (∆L1) = F1.L1/A1.Y1

= F1× L1/πr²×Y1

= 98×1.5/3.14 × (1.25×10^-3)²×2×10¹¹

= 1.5 × 10^-6 m

For brass wire

________________

Tension in brass wire(F2) = 6g= 6×9.8

= 58.8N

Length of brass wire (L2) = 1 m

Young's modulus (Y2) = 0.91 × 10¹¹

we know,

change in Length (∆L2) = F2×L2/A2×Y2

= 58.8×1/{3.14 × (1.25×10^-3)× 0.91 × 10¹¹}

= 1.3 × 10^-6 m

Explanation:

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