Two wires of equal lengths are made of the same material. Wire A has a diameter that is twice as that of wire B. If identical weights are suspended from the ends of these wires, the increase in length is [EAMCET 1983; MP PMT 1990; MP PET 1995]
A) Four times for wire A as for wire B B) Twice for wire A as for wire B C) Half for wire A as for wire B D) One-fourth for wire A as for wire B
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correct answer is C of ur question
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Answer:
(d)
Explanation: l = FL/AY so l is directly proportional to 1/r2
Given Diameter of A = 2 × Diameter of B ∴ rA = 2rB ∴ (ℓA / ℓB) = (rB / rA)2 (ℓA / ℓB) = (1/4) i.e. ℓB = 4ℓA ℓA = (ℓB / 4)
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