Two wires of length 36 CM are bent to form a square and rectangle. Which of the two fingers square and rectangle will have a greater area and by how much
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heya mate here is your answer
length of wire = perimeter of Square and rectangle
but perimeter of square = 4s
36 = 4s
s = 36/4
s = 9cm
now , area of square = s^2 = 9^2 = 81cm
but to find the area of rectangle data is not sufficient
length of wire = perimeter of Square and rectangle
but perimeter of square = 4s
36 = 4s
s = 36/4
s = 9cm
now , area of square = s^2 = 9^2 = 81cm
but to find the area of rectangle data is not sufficient
karthikadevi:
Hi
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