Question

two wires of length 44 CM are Bent to form a square and rectangle the breadth of the rectangle format is 5 cm which of the two figure square and rectangle will have a great area and by how much?​

Answer 1

Answer:

wire in the form of square have greater area than rectgle by 36 cm square

Step-by-step explanation:

perimeter of saqure 44 than side = 11 so area = 11×11 = 121 cm square

now side of rectangle = 17 by formula of perimetr of rectnagle so area17×5 = 85cm saqure

so difference is 36 cm square

Answer 2

Answer:

square

Step-by-step explanation:

perimeter of rectangle = 2(l+b)

44=2l+10

34=2l

l=17cm

area enclosed by rectangle= l*b

=> 17*5

=> 85 sq.cm

perimeter of square = 4*s

44=4*s

s=11

area enclosed by square= s^2

=> 11^2

=> 121 sq.cm

121-85=36 sq.cm