Two wires of same length are shaped into a square and a circle
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Answer:
Let length of wire be l. For a square loop, side of square
4
l
.
Hence its magnetic moment
M
sq
=iA=i[
4
l
]
2
=
16
il
2
Radius of a circular loop r=
2π
l
.
Hence, its magnetic moment
M
cir
=iA=iπr
2
M
cir
=iπ[
4π
2
l
2
]=
4π
il
2
⇒
M
cir
M
sq
=
4
π
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