Question

Two wires of same material have their lengths in the ratio of 2 is to 3 and radius 8 is to 9 same potential difference is applied between their ends separately calculate the ratio of current through them.


Plz answer it's very urgent​

Answer 1

Answer:

First wire has more current

Explanation:

Since, V=IR

So, I= V/R

R = rho ×l/A

So R1= rho × 2/ 8×8 = rho /32

R2= rho× 3/9×9 = rho/ 27

So current through the first wire will be more, i.e 32V/ rho and second wire has less current, i.e 27V/rho.