Question

Two workers a and b working together completed ajob in 5 days.if a worked twice as efficently as he actually did and b worked 1/3 as efficiently as he actually did,the work would havebeen completed in 3 day.to complete the job alone a would require

Answer 1

$\color{red}{ \boxed{THanks for asking this question}}$

$\color{green}{ \boxed{ \bold{ Good Morning}}}$

$\color{blue}{ \boxed{ \bold{have a great day}}}$

$\color{violet}{ \boxed{ \bold{Required Answer}}}$

$\color{brown}{ \boxed{ \bold{let \: to \: be \: work \: done \: by \: a = \frac{1}{a} }}}$

$\color{green}{ \boxed{ \bold{let \: to \: be \: work \: done \: by \: b = \frac{1}{b} }}}$

$\color{maroon}{ \boxed{ \bold{then}}}$

$\color{green}{ \boxed{ \bold{One \: Day's \: work of \: A \: and \: B \: \: together, \: 1/A + 1/B = 1/5. ------ (i)}}}$

$\color{red}{ \boxed{ \bold{ \underline{1/A + 1/B = 1/5. ------ (i)}}}}$

$\color{r}{ \boxed{ \bold{When \: A \: works \: with \: twice \: efficiency,}}}$

$\color{indigo}{ \boxed{ \bold{ \underline{2/A + 1/3B = 1/3. --------(ii)}}}}$

$\color{indigo}{ \boxed{ \bold{ \underline{according \: to \: the \: \: question}}}}$

$\color{violet}{ \boxed{ \bold{ \underline{on \: solving \: equations \: (i) and (ii)}}}}$

$\color{blue}{ \boxed{ \bold{ \underline{ A = 25/4 = 6(1/4)}}}}$

$\color{red}{ \boxed{ \bold{ \underline{answer \: - - > \: 6( \frac{1}{4})}}}}$

$\color{maroon}{ \boxed{ \bold{ \underline{BE BRAINLY}}}$