two year ago a father was five times as old as his son.two years later his age will be 8 more than three times the age of the son.set up two linear equations in two variables,to express the above statement.
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Let's assume present age is
Father = X
Son = Y
2 years ago
Age of father = X-2
Age of son Y-2
According to question
5(Y-2)=X-2 ........ 1
2 years later
Age of father = X + 2.
Age of son = Y+2
According to question
3(Y+2)+8 = X+2
Father = X
Son = Y
2 years ago
Age of father = X-2
Age of son Y-2
According to question
5(Y-2)=X-2 ........ 1
2 years later
Age of father = X + 2.
Age of son = Y+2
According to question
3(Y+2)+8 = X+2
Rajnishkd:
age of son = 10 Age of father = 42
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