Math, asked by kumarivaishnavi165, 8 months ago

Two year ago father was three time as old as his son and two year hence twice his ago will be equal to five time that of his son .find their present ages.

Answers

Answered by KunjSingh46
1

Answer:

Keywords - ago = [ —]

* Let's assume their present ages as x.

Firstly we will find father's previous age

son \: age \:  = 5years \: old \:  \\ 5 \times 3 = 15 \:

So the father's age was 15 at that time.

So here we got the age of father and son, let's do it's operation -

x - 15 = 2

x = 15 (minus with be plus)

= 15 + 2

= 17

And if same is done with son's age so the answer will be 7.

Ans: The present age of father and son is 17 and 7 respectively.

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