Question

two year ago,father was three time as old as his son and two years hence, twice his age will be equal to give time that og his son. find their age

Answer 1

Answer:Let father's age be x and sons age be y

2 years ago :

X-2=3 (y-2)

3y-x=4

2 years hence:

2 (x+2)=5 (y+2)

2x+4=5y+10

2x-5y=6

Now we equate the equations

2 (3y-x=4)

-5y+2x=6

6y-2x=8

-5y+2x=6

now subtract the above 2 equatio

y=14

Put the value of y in any of the equation where x comes out to be 38

So:

y is 14

x is 38