Two year ago father was three times as old as son and two years hence his
age will be equal to five times that of his
son. Find their present age
Answers
Answered by
19
Let son's age = x
Two years ago son's age= x-2.
His Father's age at that time = 3(x-2).
Present age of Father = 3x-6+2=3x-4
Two years hence father's age=3x-4+2=3x-2.
Two years hence son's age = x+2.
Given :-5*(x+2)=2*(3x-2)
5x + 10= 6x - 4
10+4=6x-5x
14=x
SON'S PRESENT AGE : 14 years.
FATHER'S PTESENT AGE: 38 years.
Similar questions