Question

two years ago a father was five times as old as his son 2 years later his age will 8 more than three times the age of the son find the present ages of father and son​

Answer 1

Answer:

X=2 y=2

Step-by-step explanation:

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Answer 2

Answer:

Son is 10 years old and his father is 42 years old.

Step-by-step explanation:

Let the present age of son be x years.

Let the present age of father be y years.

According to question

2 years ago

y-2=5(x-2)

y-2=5x-10

5x-y=8.....(1)

2 years later

y+2=3(x+2)+8

y+2=3x+6+8

y-3x=12......(2)

From (2),y=12+3x

Put y in (1)

5x-(12+3x)=8

5x-12-3x=8

2x=20

x=10

y=42