Two years ago a father was five times as old as his son . Two years later his age will be 8 more than three times the age of the son . Find the present ages of father and son
Answers
Answer:
Age of father = 37 years
Age if his son = 9 years
Step-by-step explanation:
let the age of father be x
and the age of his son be y
given that,
Two years ago a father was five times as old as his son
so,
x - 2 = 5(y - 2)
x - 2 = 5y - 10
x - 5y = -10 + 2
x - 5y = -8. ....(1)
also given that,
Two years later his age will be 8 more than three times the age of the son
so,
According to the question,
x + 2 = 3(y + 2) + 8
x + 2 = 3y + 6 + 8
x - 3y = 14 - 2
x - 3y = 12. ...(2)
now,
we have,
x - 5y = -8. ....(1)
x - 3y = 12. ...(2)
(1) - (2)
x - 5y - (x - 3y) = - 8 - 12
x - 5y - x + 3y = -18
-2y = -18
y = -18/-2
y = 9
putting the value of y on (1).
x - 5y = -8
x - 5(9) = -8
x - 45 = -8
x = -8 + 45
x = 37
y = 9
so,
___________________
Age of father = 37 years
Age if his son = 9 years
Answer:
Age of father = 37 years
Age if his son = 9 years
Step-by-step explanation:
let the age of father be x
and the age of his son be y
ATQ,
x - 2 = 5(y - 2)
x - 2 = 5y - 10
x - 5y = -8. ....(1)
also,
x + 2 = 3(y + 2) + 8
x + 2 = 3y + 6 + 8
x - 3y = 14 - 2
x - 3y = 12. ...(2)
now, from (1) and (2)
(1) - (2)
x - 5y - (x - 3y) = - 8 - 12
x - 5y - x + 3y = -18
-2y = -18
y = -18/-2
y = 9
putting the value of y on (1).
x - 5y = -8
x - 5(9) = -8
x = -8 + 45
x = 37
so,