Question

Two years ago, a father was five times
as old as his son. Two years later,
his age will be 8 more than three times
the age of the son. Find the present ages
of father and son
​

Answer 1

Answer:

father = 42

son = 10

Step-by-step explanation:

(s-2) = x

(f-2) = 5x

s = x+2

f = 5x + 2

(s+2) = x+4

(f+2) = (5x + 4)

according to the question

(5x+4) = 3(x+4) + 8

.

.

x = 8