Two years ago a father was five times as old as his son. Two years later his will eight than that of three times the age of his son. Find the age of the father?
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Answered by
0
Answer:
Father's age = 5x = 5 × 6 = 30 years
Son's age = x = 6 years
Step-by-step explanation:
Two years ago:
Father's age = 5x
Son's age = x
Two years later:
Father's age = 5x + 2
Son's age = x + 2
8 + 3(x + 2) = 5x + 2
8 + 3x + 6 = 5x + 2
14 + 3x = 5x + 2
3x - 5x = 2 - 14
-2x = -12
x = -12/-2
x = 6
Father's age = 5x = 5 × 6 = 30 years
Son's age = x = 6 years
Check ⇒
Two years later:
Father's age = 5x + 2 = 30 + 2 = 32
Son's age = x + 2 = 6 + 2 = 8
8 + (3 × 8) = 32
8 + 24 = 32
32 = 32
L.H.S = R.H.S
Hence, verified.
The answer is correct.
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Answered by
2
Answer:
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