compute the value of z given that (x=2,y=3,a=4,b=5)
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Solution :
(i) From given matrices, we find that,
y=4
z=3
x=1
(ii)From given matrices, we find that,
x+y=6⇒y=6−x→(1)
5+z=5⇒z=0
xy=8⇒x(6−x)=8
⇒6x−x2=8
⇒x2−6x+8=0
⇒(x−4)(x−2)=0
⇒x=4orx=2
When x=4,y=2
When x=2,y=4
(iii) From given matrices, we find that,
x+y+z=9→(1)
x+z=5→(2)
y+z=7→(3)
From (1) and (3),
x+(y+z)=9⇒x+7=9⇒x=2
From (1) and (2),
(x+z)+y=9⇒5+y=9⇒y=4
4+z=7⇒z=3
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