two years ago,a father was five times as old as his son.two years later,his age will be 8 more than three times the age of the son . find the present ages of father and son .
Answers
Step-by-step explanation:
2 years ago,son was x years old
father was 5x years old
at present son is x+2,father is 5x+2
2years later,son is x+4,father is 5x+4
5x+4=3(x+4)+8
5x-3x=12+8-4=16
2x=16
x=16/2=8
present age of the son is8+2years=10 years
present age of the father is 5.8+2=42 years
GivEn:
- Two years ago, a father was five times as old as his son.
- Two years later, his age will be 8 more than three times the age of the son.
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To find:
- Present age of father and his son.
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SoluTion:
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☯ Let present age of father be x years.
☯ Let present age of his son be y years.
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Two years ago,
Father was five times as old as his son.
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Therefore,
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Ages before two year,
- Age of father = (x - 2) years
- Age of his son = (y - 2) years
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Two year later,
Age of father will be 8 more than three times the age of the son.
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Therefore,
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Ages after two year,
- Age of father = (x + 2) years
- Age of his son = (y + 2) years
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Present age of father is 42 years and Present age of his son is 20 years.