Math, asked by rigvednaik, 5 months ago




Two years ago, a man's age. was
three times the
square of this son's age. In three
To three year time his
age will be four times his son's age Find their
present age.​

Answers

Answered by sprao53413
0

Answer:

Their present ages are are 29 and 5 years

Let the present ages be x, y

x-2=3(y-2)^2

x+3=4(y+3)

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