Question

Two years ago, a man was five times as old as his son. Two years later, his age will be 8 more than three times. the age of his son. Find their present ages.

Answer 1

look at attachment for solution.

Answer 2

$\underline{\bold{Solution:-}}$

Let the present age of son be x.

According to condition, before 2 years

Age of son = x-2

Age of man = 5(x-2)=5x-10

Present age of man = 5x - 8

⭐ After two years,

Man's age = 5x - 6

Son's age = x + 2

According to question, after 2 years

Father's age = 3(son's age) + 8

$5x -6 = 3(x + 2) + 8 \\ \\ 5x -6= 3x + 6 + 8 \\ \\ 5x -3x = 14 +6 \\ \\ 2x = 20 \\ \\ x = \frac{12}{2} \\ \\ x = 10$

Present age of son = 10 years

Present age of father= 5×10-8 = 42 years