Question

Two years ago a man was six times as old as his son. In 18 years, he will be twice as old as his son. What are thelr present ages of the man and his son?
1.34 and 7 years
2. 34 and 9 years
3.32 and 7 years
4.32 and 13 years​

Answer 1

Answer:

3. 32 and 7 years  

Step-by-step explanation:

Let the present age of man is M and that of son is S

Two years ago a man was six times as old as his son

M-2 = 6(S-2) = 6S-12

M = 6S-10

In 18 years, he will be twice as old as his son

M+18 = 2(S+18)

by substituting M=6S-10 in second equation

6S-10 + 18 = 2S+36

4S = 28

S = 7

M=6*7-10 = 32

Answer 2

Step-by-step explanation:

hi mate....................

c is correct