Question

Two years ago, a man was six times as old as his son. In 18 years, he
will be twice as old as his son. The age of the man (in years) is​

Answer 1

Step-by-step explanation:

Let the present ages of father and son be x and y, respectively.

As per the problem, six years ago,

(x−6)=3(y−6)

Six years later, (x+6)=2(y+6)

Solving these two equations, we get father's age is 42 years, and son's age is 18 years.