Question

Two years ago, dilip was 3 times as old as his son and two years hence twice his age will be equal to 5 times that of his son's age. Find their present ages.​

please answer it fast ​

Answer 1

Step-by-step explanation:

let dilip current age be x

sons current age be y

2 years ago

dilips age x-2

son age y-2

1) x-2=3(y-2)

X-2 = 3y -6

x-3y =-4

2 years later

dilip age x+2

son age y+2

2) 2(x+2) = 5(y+2)

2x+4 = 5y +10

2x+5y = 6

solving the two equations

2x + 5y = 6

2(x -3y = -4)

2x+5y=6

2x-6y=-8

Answer 2

Given :-

→ Let Dilip's son's age 2 years ago be x years.

Then, Dilip's age 2 years ago = ( 3x ) years

Thus , the son's age 2 years hence (x + 4) years.

Thus , the son's age 2 years hence (x + 4) years. Dilip's age 2 years hence (3x + 4) years.

→ 2 ( 3x + 4 ) = 5 ( x + 4 )

→ 6x + 8 = 5x +20

→ x = 12.

∴ Dilip's son's age 2 years ago = 12 years and Dilip's age 2 years ago = 36 years.

∴ son's present age = 14 years, and

Dilip's present age = 38 years.

Thank You!