Question

Two years ago, Dilip was three times as old as his son and two years hence,twice his age will be equal to five times that of his son find their present ages.

Answer 1

let two year ago dilip age was 3x and his son x

now

2 Dilip present age =5 his son present age

2 (3x+2)=5 (x+2)

6x+4=5x+10

x=6

3x=18

present age dilip 20 and his son 8

Answer 2

Step-by-step explanation:

let the present age of Dilip x year's

and his son age is y year's repectively.

ATQ

two year's ago

x-2=3(y-2)

x-2=3y-6

x-3y+4=0...................(1)

and

two year's hence

2x=5y

x=5y/2

5y/2-x=0.......................(2)

adding (1)+(2)

x-3y+4+5y/2-x=0

-3y+4+5y/2=0

(-6y+8+5y)/2=0

-6y+8+5y=0

-y=-8

y=8

substitute y value in (1)

x-3×8+4=0

x-24+4=0

x-20=0

x=20

therefore the present ages of

Dilip is 20 year's

and his son is 8 year's.