Question

two years ago dilip was three times as old as his son and two years hence, twice his age will be equal to the five times his son find their present age

Answer 1

Let the present age of Dilip's son be x. Age of Dilip's son 2 years ago = (x - 2) Age of Dilip 2 years ago = 3(x - 2) Age of Dilip's son after 2 years = (x + 2) Age of Dilip after 2 years = 3(x - 2) + 4 = 3x - 6 + 4 = (3x - 2)Twice the age of Dilip is equal to five times the age of his son. 2(3x - 2) = 5(x + 2) 6x - 4 = 5x + 10 6x - 5x = 10 + 4 x = 14 Present age of Dilip's son is 14 years. Age of Dilip 2 years ago = 3(14 - 2) = 36 years Present age of Dilip = 36 + 2 = 38 years.

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Answer 2

Given :-

→ Let Dilip's son's age 2 years ago be x years.

Then, Dilip's age 2 years ago = ( 3x ) years

Thus , the son's age 2 years hence (x + 4) years.

Dilip's age 2 years hence (3x + 4) years.

→ 2 ( 3x + 4 ) = 5 ( x + 4 )

→ 6x + 8 = 5x +20

→ x = 12.

∴ Dilip's son's age 2 years ago = 12 years and Dilip's age 2 years ago = 36 years.

∴ son's present age = 14 years, and

Dilip's present age = 38 years.

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