a body when acted upon by a force 10 kgs gets displayed by 0.5 calculate the work done by the force when the displacement 1) is the direction of the force 2) at an angle of 60° with a force and the 3) normal to the force (g=10N kg —¹
Answers
Answered by
3
Work done = force * displacement * cos °
And force = mass * acceleration
= 10 * 10 = 100N
Therefore the work done = 100 * 1m * cos (60)
= 100 * 0.5 = 50 joules
Bye
Hope you liked it
Mark me brainliest
And force = mass * acceleration
= 10 * 10 = 100N
Therefore the work done = 100 * 1m * cos (60)
= 100 * 0.5 = 50 joules
Bye
Hope you liked it
Mark me brainliest
Answered by
0
The answer is 50Nm or 50Joule
Explanation:
Force=mass×acceleration
=10×10=100N
Displacement=0.5m
Workdone=force×displacement
=100N×0.5m=50J
Similar questions