Question

Two years ago. Dilip was three times as old us his son and two years hence, twice his age
will be equal to five times that of his son. The present age of son and Dilip are
14.38 years
16, 40 years) 12. 36 years (0) None
In linear equation in one variable

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Answer 1

Solution :

Let us assume that the present age of Dilip is x years .

Two years , the age of Dilip was ( x - 2) years .

( x - 2 ) = 3 [ His sons ago 2 years ago ]

=> [ His sons age 2 years ago ] = ( x - 2)/3

His sons present age

=> ( x - 2)/3 + 2

=> ( x - 2 + 6)/3

=> ( x + 4)/3

After 2 years

• His age

=> ( x + 2 ) years

• His sons age

=> ( x + 4)/3 + 2

=> [ x + 10]/3 years

Now , 2( x + 2) = 5 × ( x + 10)/3

=> 6( x + 2) = 5( x + 10)

=> 6x + 12 = 5x + 50

=> x = 38

Son's age :

( 38 + 4)/3

=> 14

Hence , their present ages are 14 years and 38 years respectively.

Thus , option A is correct .

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Answer 2

Answer in attachment

Please verify my answer