Question

Two years ago, Dilip was three times old as his son and two years hence twice his age will be equal to five times that of his son. Find their present age

Answer 1

Step-by-step explanation:

Lat the age od Dilip be x and his son be y.

According to question:

(x-2)=3(y-2)=>x-3y=-4 (1)

(x+2)2=5(y+2)=> 2x+4=5y+10=>

2x-5y=6. (2)

from 1 & 2 (substitution method)

x=-4+3y. (3)

3 in 2

2(-4+3y)-5y=6

-8+6y-5y=6

y=14. (4)

4 in 3

x=-4+3(14)

x=-4+42

x=38.

Verify:-

38-3(14)=-4

38-42=-4✔️

2(38)-5(14)=6

76-70=6✔️.

hope helps u!

Answer 2

Given :-

→ Let Dilip's son's age 2 years ago be x years.

Then, Dilip's age 2 years ago = ( 3x ) years

Thus , the son's age 2 years hence (x + 4) years.

Dilip's age 2 years hence (3x + 4) years.

→ 2 ( 3x + 4 ) = 5 ( x + 4 )

→ 6x + 8 = 5x +20

→ x = 12.

∴ Dilip's son's age 2 years ago = 12 years and Dilip's age 2 years ago = 36 years.

∴ son's present age = 14 years, and

Dilip's present age = 38 years.

Thank You!