Math, asked by info5076, 9 months ago

two years ago farther was three times as old as his son and two years hence twice his age will be equal to five times that a of his son find their present ages

plz answer with clear explanation​

Answers

Answered by MsPRENCY
11

\textbf {\underline{\underline {Step\: - by\: - Step\: Explanation :}}}

_________________________________________

\huge\sf\purple {Given :}

Two years ago father was 3 times as old as his son.

Let son's age be x

so, Father's age ( 2 yrs ago ) = 3 ( x - 2 )

Son' s age ( 2 yrs ago ) = 3x - 2

 \huge\sf\purple {To\:find :}

Present age of father and son.

\huge\sf\purple {Solution :}

● Present age of father = 3 ( x - 2 ) + 2

=> 3x - 6 + 2 = 3x - 4

it is given 2 years hence,

3x - 4 + 2 = 3x - 2

\sf {According\: to\: Question}

5(x+ 2) = 2 ( 3x - 2 )

==> 5x + 10 = 6x - 4

==> 10 + 4 = 6x - 5x

==> 14 = x

\therefore Present age of son is 14 years.

Present age of father = 3x - 4

= 3 × 14 - 4

=> 42 - 4 = 38 years

\sf\blue {Answer:} \sf {Present\: age\:of\:father\: and\: Son\:are\: 14\: and\: 38, \:respectively. }

\huge\mathscr\red {Be\: brainly!!!}

Answered by Anonymous
77

Given:

Two years ago father was 3 times as old as his son.

Let son's age be x

so, Father's age ( 2 yrs ago ) = 3 ( x - 2 )

Son' s age ( 2 yrs ago ) = 3x - 2

\huge\tt\green{To\:find :}

Present age of father and son.

\huge\tt\green {Solution :}

● Present age of father = 3 ( x - 2 ) + 2

=> 3x - 6 + 2 = 3x - 4

it is given 2 years hence,

3x - 4 + 2 = 3x - 2

\tt {According\: to\: Question}

5(x+ 2) = 2 ( 3x - 2 )

==> 5x + 10 = 6x - 4

==> 10 + 4 = 6x - 5x

==> 14 = x

Present age of son is 14 years.

Present age of father = 3x - 4

= 3 × 14 - 4

=> 42 - 4 = 38 years


Anonymous: Great ! ❤️
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