two years ago farther was three times as old as his son and two years hence twice his age will be equal to five times that a of his son find their present ages
plz answer with clear explanation
Answers
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Two years ago father was 3 times as old as his son.
Let son's age be x
so, Father's age ( 2 yrs ago ) = 3 ( x - 2 )
Son' s age ( 2 yrs ago ) = 3x - 2
Present age of father and son.
● Present age of father = 3 ( x - 2 ) + 2
=> 3x - 6 + 2 = 3x - 4
it is given 2 years hence,
3x - 4 + 2 = 3x - 2
5(x+ 2) = 2 ( 3x - 2 )
==> 5x + 10 = 6x - 4
==> 10 + 4 = 6x - 5x
==> 14 = x
Present age of son is 14 years.
Present age of father = 3x - 4
= 3 × 14 - 4
=> 42 - 4 = 38 years
Given:
Two years ago father was 3 times as old as his son.
Let son's age be x
so, Father's age ( 2 yrs ago ) = 3 ( x - 2 )
Son' s age ( 2 yrs ago ) = 3x - 2
Present age of father and son.
● Present age of father = 3 ( x - 2 ) + 2
=> 3x - 6 + 2 = 3x - 4
it is given 2 years hence,
3x - 4 + 2 = 3x - 2
5(x+ 2) = 2 ( 3x - 2 )
==> 5x + 10 = 6x - 4
==> 10 + 4 = 6x - 5x
==> 14 = x
Present age of son is 14 years.
Present age of father = 3x - 4
= 3 × 14 - 4