Math, asked by info5076, 11 months ago

two years ago farther was three times as old as his son and two years hence twice his age will be equal to five times that a of his son find their present ages

plz answer with clear explanation​

Answers

Answered by MsPRENCY
11

\textbf {\underline{\underline {Step\: - by\: - Step\: Explanation :}}}

_________________________________________

\huge\sf\purple {Given :}

Two years ago father was 3 times as old as his son.

Let son's age be x

so, Father's age ( 2 yrs ago ) = 3 ( x - 2 )

Son' s age ( 2 yrs ago ) = 3x - 2

 \huge\sf\purple {To\:find :}

Present age of father and son.

\huge\sf\purple {Solution :}

● Present age of father = 3 ( x - 2 ) + 2

=> 3x - 6 + 2 = 3x - 4

it is given 2 years hence,

3x - 4 + 2 = 3x - 2

\sf {According\: to\: Question}

5(x+ 2) = 2 ( 3x - 2 )

==> 5x + 10 = 6x - 4

==> 10 + 4 = 6x - 5x

==> 14 = x

\therefore Present age of son is 14 years.

Present age of father = 3x - 4

= 3 × 14 - 4

=> 42 - 4 = 38 years

\sf\blue {Answer:} \sf {Present\: age\:of\:father\: and\: Son\:are\: 14\: and\: 38, \:respectively. }

\huge\mathscr\red {Be\: brainly!!!}

Answered by Anonymous
77

Given:

Two years ago father was 3 times as old as his son.

Let son's age be x

so, Father's age ( 2 yrs ago ) = 3 ( x - 2 )

Son' s age ( 2 yrs ago ) = 3x - 2

\huge\tt\green{To\:find :}

Present age of father and son.

\huge\tt\green {Solution :}

● Present age of father = 3 ( x - 2 ) + 2

=> 3x - 6 + 2 = 3x - 4

it is given 2 years hence,

3x - 4 + 2 = 3x - 2

\tt {According\: to\: Question}

5(x+ 2) = 2 ( 3x - 2 )

==> 5x + 10 = 6x - 4

==> 10 + 4 = 6x - 5x

==> 14 = x

Present age of son is 14 years.

Present age of father = 3x - 4

= 3 × 14 - 4

=> 42 - 4 = 38 years


Anonymous: Great ! ❤️
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