Question

Two years ago,
father was three times as old as his son and two years hence, twice is equal to five times that of his son. Find their present ages.
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Answer 1

Step-by-step explanation:

let father's present age=x years

let son's present age=y years

according to question,

x-2=3(y-2)

x-2=3y-6

x=3y-4 .......................... (1)

x+2 = 2(y+2)

x+2 = 2y+4

x=2y+2 ......................... (2)

from (1) &(2)

3y-4=2y+2

y=6

put this value in (1)

x=3×6-4

x=14

so

father's present age=14years

son's present age=6years