Math, asked by rajpriya3186, 8 months ago

two years ago father was three times as old as his son and two years hence twice his age will be equal to five times that of his son find their present ages​

Answers

Answered by gopibalu00
1

Answer:

9294

Step-by-step explanation:

let now the age of father be x

and son age be y

two years ago,

father age=x-2

son's age be y-2

relationship is. x-2=3(y-2)

####### x-y+4=0

In the same way,2x-5y-6=0

solving them

son's age y=

Answered by Shivangi128
1

Answer:

Hey mate here's your answer

Hope it helps

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