two years ago father was three times as old as his son and two years hence twice his age will be equal to five times that of his son find their present ages
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Answer:
9294
Step-by-step explanation:
let now the age of father be x
and son age be y
two years ago,
father age=x-2
son's age be y-2
relationship is. x-2=3(y-2)
####### x-y+4=0
In the same way,2x-5y-6=0
solving them
son's age y=
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Hey mate here's your answer
Hope it helps
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