Question

two years ago, father was three times as old as his son and two years hence,twice his age will be equal to five times that of his son. find their present ages​

Answer 1

Answer:

father=38 and son = 14

Step-by-step explanation:

assume current ages as x and y respectively

so before 2 years the equation that can be formed will be

(x-2)=3(y-2)

after 2 years hence, equation can be form is

2(x+2)=5(y+2)

solving this both equation, we will find x=38 and y=14 which are the current ages of father and son respectively..

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