Question

two years ago father was three times as old as his son and two years has twice his age will be equal to five times that of his son find their present age

Answer 1

Son=X
Father=3X

Now Son = X+2
Father = 3X+2

ATQ

5×(X+2+2) = 2×(3X+2+2)

5X+20 = 6X+8

X=12

Present age of Son is (X+2)=12+2=14

Present age of Father is (3X+2) = 36+2=38

$\huge \boxed {\textt \fcolorbox \fcolorbox \boxed {Father=38 years}}}$

$\huge \boxed {\textt \fcolorbox \fcolorbox \boxed {Son=14 years}}}$

$\huge \boxed {\textt \fcolorbox \fcolorbox \boxed {Mark It Brainliest}}}$