two years ago ,father was three times as old as his sonand two years hence,twice his age will be equal to five times that of his son.find their present ages.
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Let age of son before 2 yrs be x
Father = 3x
2(3x+4)= 5(x+4)
6x +8 = 5x + 20
x = 12
age before 2 years = 12
present age = 14yrs
Age of father = 3x + 2
= 36 + 2
= 38
Father = 3x
2(3x+4)= 5(x+4)
6x +8 = 5x + 20
x = 12
age before 2 years = 12
present age = 14yrs
Age of father = 3x + 2
= 36 + 2
= 38
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