Math, asked by vijaytrivedi711, 2 months ago

Two years ago, Motu was three times her daughter's age. Two years later, Motu will be twice her age, five times her daughter's age. So find out the current age of both.

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Answered by Anonymous

Step-by-step explanation:

Solution:

Suppose 2 years ago Motu's daughter age be x years and suppose Motu's age be 3 x years.

Present age of Motu's daughter=x+2 years

Present age of Motu=3x+2 years

After 2 years,

Motu's daughter age will be x+2+2=x+4 years

Motu's age will be 3x+2+2=3x+4 years

Now given that -Two years later, Motu will be twice her age, five times her daughter's age,so if we multiply 2 from the age of Motu's daughter after 2 years, it will be equal to the age of Motu after 2 years.

ACQ,

3x+4=2(x+4)

3x+4=2x+8

x=4

Present age of Motu =3×4+2=14 years

Present age of Motu's daughter=6 years

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Two years ago, Motu was three times her daughter's age. Two years later, Motu will be twice her age, five times her daughter's age. So find out the current age of both.​

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Solution:

Two years ago, Motu was three times her daughter's age. Two years later, Motu will be twice her age, five times her daughter's age. So find out the current age of both.