Math, asked by sowmiya5, 1 year ago

two yrs ago, priya was twice a old as kiran. now the difference is 10yrs. find their ages

Answers

Answered by supersonu
30
Hi,

Here's ur answer,

Let Kiran's age = x

So,Kiran's age before two years = x-2

So, Priya's age before 2 years = 2(x-2) = 2x-4

Kiran's present age = x

Priya's present age = 2x-4+2 = 2x-2

According to question,

2x-2-x = 10

=>x-2 = 10

=> x = 10+2 = 12

So, Kiran's present age = 12

Priya's present age = 2x - 2 = 2×12-2 = 24-2 = 22

So, Kiran's age = 12 and Priya's age = 22

HOPE IT HELPS (^_^)


Answered by PoojaBurra
4

Their ages are 12 and 22.

Given - Ages two years ago and difference in present years

Find - Ages

Solution - Let the age of Kiran be x. So, age of Kiran two years ago = x-2.

Age of Priya = 2(x-2)

Age of Priya = 2x - 4

Current age of Priya = 2x - 4 + 2

Current age of Priya = 2x - 2

Representing their current ages -

2x - 2 - x = 10

x = 10 + 2

x = 12

Current age of Priya = 2*12 - 2

Current age of Priya = 24 - 2

Current age of Priya = 22

Hence, age of Kiran and Priya is 12 and 22.

#spj5

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