Two zeroes of p(x)= x3-6x2+11x-6 are 2 and 3. Find the trd zero
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Answered by
3
sum of zeros = 6
2+3+x = 6
x =1
the third zero will be 1
2+3+x = 6
x =1
the third zero will be 1
Answered by
1
sum of zeros = -d/a = 6
therefore 2 + 3 + X = 6
X = 1
therefore 2 + 3 + X = 6
X = 1
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