Question

Type-
find the derivative of the following
1.sinx . x power 2+2​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Explanation:

Note that we can write this more compactly as csc2x as cosec xis 1sinx.

But to take the derivative this form in terms of sin is more useful. Use the quotient rule for the overall fraction and the chain rule to differentiate sin2x.

ddx[1sin2x]=sin2x⋅0−1⋅2sinxcosxsin4x

=−2sinxcosxsin4x=−2cosxsin3x

=−2cotxcsc2x