Question

U={1,2,3,4,5,6,7,8},. A={1,2,3,4},. B={2,4,6} and C={1,2,5},. Then write down the elements of A' ⋂ (B-C)

Answer 1

Answer:

A'=U-A

A'={1,2,3,4,5,6,7,8}-{1,2,3,4}

A'={5,6,7,8}

(B-C) ={(2,4,6)-(1,2,5)}

(B-C) ={}

A'n(B-C)=(5,6,7,8)n()

A'n(B-C)={ }

Answer 2

Answer:

Elements of ${A}'\cap \left ( B - C \right ) = \left \{ 6 \right \}$

Step-by-step explanation:

Given  $U = \left \{ 1,2,3,4,5,6,7,8 \right \}$

                $A = \left \{ 1,2,3,4 \right \}$

                 $B = \left \{ 2,4,6 \right \}$

                   $C = \left \{1,2,5 \right \}$

    We know complement

                 ${A}' = U - A$            

                         $= \left \{ 1,2,3,4,5,6,7,8 \right \} - \left \{ 1,2,3,4 \right \}$

                  or  ${A}' = \left \{5,6,7,8 \right \}$

                 

Difference   $\left ( B - C \right ) = \left \{ 2,4,6 \right \} - \left \{ 1,2,5 \right \}$

or   $\left ( B - C \right ) = \left \{ 4,6 \right \}$

Now , ${A}'\cap \left ( B - C \right ) = \left \{ 5,6,7,8 \right \}\cap \left \{ 4,6 \right \}$

${A}'\cap \left ( B - C \right ) = \left \{ 6 \right \}$